The coefficient of apparent expansion of merc | vedclass

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(A) The coefficient of real expansion of mercury $(\gamma_{real})$ is constant regardless of the vessel used.We know the relation: $\gamma_{real} = \g

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$9 	imes 10^{-6} \, ^{\circ}C^{-1}$

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(A) The coefficient of real expansion of mercury $(\gamma_{real})$ is constant regardless of the vessel used.We know the relation: $\gamma_{real} = \gamma_{app} + \gamma_{vessel}$,where $\gamma_{vessel} = 3\alpha$.For the glass vessel: $\gamma_{real} = 153 	imes 10^{-6} + \gamma_{glass}$.For the steel vessel: $\gamma_{real} = 144 	imes 10^{-6} + 3\alpha_{steel}$.Given $\alpha_{steel} = 12 	imes 10^{-6} \, ^{\circ}C^{-1}$,so $\gamma_{steel} = 3 	imes 12 	imes 10^{-6} = 36 	imes 10^{-6} \, ^{\circ}C^{-1}$.Equating the two expressions for $\gamma_{real}$:$153 	imes 10^{-6} + \gamma_{glass} = 144 	imes 10^{-6} + 36 	imes 10^{-6}$.$153 	imes 10^{-6} + \gamma_{glass} = 180 	imes 10^{-6}$.$\gamma_{glass} = (180 - 153) 	imes 10^{-6} = 27 	imes 10^{-6} \, ^{\circ}C^{-1}$.Since $\gamma_{glass} = 3\alpha_{glass}$,we have $3\alpha_{glass} = 27 	imes 10^{-6} \, ^{\circ}C^{-1}$.Therefore,$\alpha_{glass} = 9 	imes 10^{-6} \, ^{\circ}C^{-1}$.

The coefficient of apparent expansion of mercury in a glass vessel is $153 \times 10^{-6} \, ^{\circ}C^{-1}$ and in a steel vessel is $144 \times 10^{-6} \, ^{\circ}C^{-1}$. If $\alpha$ for steel is $12 \times 10^{-6} \, ^{\circ}C^{-1}$,then that of glass is:

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