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(B) The degree of freedom $f = 6$. For an ideal gas,the molar heat capacity at constant pressure is given by $C_P = \left(1 + \frac{f}{2}\right)R$. Su

Vedclass · Accepted Answer

$100$

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(B) The degree of freedom $f = 6$. For an ideal gas,the molar heat capacity at constant pressure is given by $C_P = \left(1 + \frac{f}{2}ight)R$. Substituting $f = 6$,we get $C_P = (1 + 3)R = 4R$. The molar heat capacity at constant volume is $C_V = \frac{f}{2}R = 3R$. The work done at constant pressure is $W = nR \Delta T = 25 \, J$. The heat absorbed at constant pressure is $Q = n C_P \Delta T$. Substituting $C_P = 4R$ and $nR \Delta T = 25 \, J$,we get $Q = n(4R) \Delta T = 4(nR \Delta T) = 4 	imes 25 \, J = 100 \, J$.

The average degree of freedom per molecule of a gas is $6$. The gas performs $25 \, J$ of work while expanding at constant pressure. The heat absorbed by the gas is ...... $J$.

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