The acceleration of a body in a non-uniform c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In non-uniform circular motion,the total acceleration $a$ is the vector sum of the radial acceleration $a_r$ and the tangential acceleration $a_t$

Vedclass · Accepted Answer

The radial acceleration and the tangential acceleration are $3\, ms^{-2}$ and $4\, ms^{-2}$ respectively.

Vedclass · Answer

(A) In non-uniform circular motion,the total acceleration $a$ is the vector sum of the radial acceleration $a_r$ and the tangential acceleration $a_t$. Since these two components are perpendicular to each other,the magnitude of the resultant acceleration is given by $a = \sqrt{a_r^2 + a_t^2}$.Given $a = 5\, ms^{-2}$.Checking option $A$: $a_r = 3\, ms^{-2}$ and $a_t = 4\, ms^{-2}$.$a = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5\, ms^{-2}$.This matches the given total acceleration. Thus,option $A$ is correct.

The acceleration of a body in a non-uniform circular motion is $5\, ms^{-2}$. Which one of the following is correct?

Similar Questions

$A$ particle moves on a circle of radius $0.1 \ m$ with a velocity $v = 1.0t$. The total acceleration at $t = 5 \ s$ will be ........ $m/s^2$.

$A$ body is moving along a circular track of radius $100 \ m$ with velocity $20 \ m/s$. Its tangential acceleration is $3 \ m/s^{2}$,then its resultant acceleration will be (in $m/s^{2}$)

$A$ particle is moving on a circular path with constant speed,then its acceleration will be

$A$ car is moving at a speed of $40\,m/s$ on a circular track of radius $400\,m.$ This speed is increasing at the rate of $3\,m/s^2.$ The acceleration of the car is ........ $m/s^2$.

$A$ particle moves in a circular path with decreasing speed. Determine the correct statement.

Vedclass Test Series

Exam Paper Generator

Online Exam Module