The "spin only" magnetic moment of Ni^{2+} in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.$Ni^{2+}$ ion has the configuration $[Ar] 3d^8$.In an aqueous solution,$Ni^{2+}$

Vedclass · Accepted Answer

$\sqrt{8} \ BM$

Vedclass · Answer

(C) The electronic configuration of $Ni$ $(Z=28)$ is $[Ar] 3d^8 4s^2$.$Ni^{2+}$ ion has the configuration $[Ar] 3d^8$.In an aqueous solution,$Ni^{2+}$ forms the octahedral complex $[Ni(H_2O)_6]^{2+}$.In the $3d$ subshell,the $8$ electrons are arranged as follows: three orbitals are doubly occupied and two orbitals are singly occupied.Therefore,the number of unpaired electrons $(n)$ $= 2$.The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n + 2)} \ BM$.Substituting $n = 2$,we get $\mu = \sqrt{2(2 + 2)} = \sqrt{8} \ BM$.

The "spin only" magnetic moment of $Ni^{2+}$ in aqueous solution would be [At. no. of $Ni = 28$]

Similar Questions

What is the spin-only magnetic moment of an element having one unpaired electron (in $BM$)?

$[Co(NH_3)_5SO_4]Br$ and $[Co(NH_3)_5Br]SO_4$ are a pair of which isomers?

The complex,$[Pt(Py)(NH_3)BrCl]$,will have how many geometrical isomers?

In the coordination complex $[CoF_6]^{3-}$,the number of unpaired electrons is equal to ......

Which of the following aquated metal ions has the highest paramagnetism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module