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The $pH$ of a $0.005 \ M \ H_2SO_4$ solution will be:

Assuming complete ionisation,the $pH$ of $0.1\,M\,HCl$ is $1$. The molarity of $H_2SO_4$ with the same $pH$ is (in $,M$)

If $0.4 \ g$ of $NaOH$ is present in $1 \ L$ of solution,then its $pH$ will be:

Calculate the volume of $0.1 \ M \ NaOH$ required to complete the neutralization of $300 \ mL$ of $HCl$ solution having $pH = 2.25$. (in $mL$)

What is the pH of $10^{-8} \ M \ HCl$ solution?

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