Solve the following pair of linear equations | vedclass

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(A) Given equations are:$(1)$ $8x + 5y = 9$$(2)$ $3x + 2y = 4$From equation $(2)$,we can express $y$ in terms of $x$:$2y = 4 - 3x$$y = \frac{4 - 3x}{2

Vedclass · Accepted Answer

$(-2, 5)$

Vedclass · Answer

(A) Given equations are:$(1)$ $8x + 5y = 9$$(2)$ $3x + 2y = 4$From equation $(2)$,we can express $y$ in terms of $x$:$2y = 4 - 3x$$y = \frac{4 - 3x}{2}$Substitute this value of $y$ into equation $(1)$:$8x + 5(\frac{4 - 3x}{2}) = 9$Multiply the entire equation by $2$ to eliminate the fraction:$16x + 5(4 - 3x) = 18$$16x + 20 - 15x = 18$$x + 20 = 18$$x = 18 - 20$$x = -2$Now,substitute $x = -2$ back into the expression for $y$:$y = \frac{4 - 3(-2)}{2}$$y = \frac{4 + 6}{2}$$y = \frac{10}{2}$$y = 5$Thus,the solution is $(x, y) = (-2, 5)$.

Solve the following pair of linear equations by the method of substitution: $8x + 5y = 9$ and $3x + 2y = 4$.

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