Solve the following pair of linear equations | vedclass

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Question

(A) Given equations are:$(1)$ $2x - y + 3 = 0$$(2)$ $y = 2x - \frac{3}{2}$Substitute the value of $y$ from equation $(2)$ into equation $(1)$:$2x - (2

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(A) Given equations are:$(1)$ $2x - y + 3 = 0$$(2)$ $y = 2x - \frac{3}{2}$Substitute the value of $y$ from equation $(2)$ into equation $(1)$:$2x - (2x - \frac{3}{2}) + 3 = 0$$2x - 2x + \frac{3}{2} + 3 = 0$$\frac{3}{2} + 3 = 0$$\frac{3 + 6}{2} = 0$$\frac{9}{2} = 0$Since $\frac{9}{2} 
eq 0$,this statement is a contradiction.Therefore,the given pair of linear equations has no solution,which means the lines are parallel. The correct option is $A$.

Solve the following pair of linear equations by the method of substitution: $2x - y + 3 = 0$ and $y = 2x - \frac{3}{2}$.

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