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(B) To solve the quadratic equation $x^{2} + 5x - 66 = 0$ by factorization,we need to find two numbers whose product is $-66$ and whose sum is $5$.The

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$-11, 6$

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(B) To solve the quadratic equation $x^{2} + 5x - 66 = 0$ by factorization,we need to find two numbers whose product is $-66$ and whose sum is $5$.These two numbers are $11$ and $-6$,since $11 	imes (-6) = -66$ and $11 + (-6) = 5$.Now,rewrite the middle term $5x$ as $11x - 6x$:$x^{2} + 11x - 6x - 66 = 0$Group the terms to factorize:$x(x + 11) - 6(x + 11) = 0$$(x - 6)(x + 11) = 0$Setting each factor to zero:$x - 6 = 0 \implies x = 6$$x + 11 = 0 \implies x = -11$Thus,the solutions are $x = 6$ and $x = -11$.

Solve the following quadratic equation using the method of factorization: $x^{2} + 5x - 66 = 0$.

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