Sita deposited ₹ 5,000 at 10% simple interest | vedclass

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Question

(c) Rate $=5 \%,$ Time $=4$ half-years

$	herefore \quad Cl =P\left[\left(1+\frac{R}{100}ight)^{T}-1ight]$

$=5000\left[\left(1+\frac{5}{100}

Vedclass · Accepted Answer

$77.50$

Vedclass · Answer

(c) Rate $=5 \%,$ Time $=4$ half-years

$	herefore \quad Cl =P\left[\left(1+\frac{R}{100}ight)^{T}-1ight]$

$=5000\left[\left(1+\frac{5}{100}ight)^{4}-1ight]$

$=5000\left(\frac{194481}{160000}-1ight)$

$=\frac{5000 	imes 34481}{160000}=₹ 1077.5$

$SI =\frac{5000 	imes 10 	imes 2}{100}=₹ 1000$

Difference $=1077.5-1000=₹ 77.5$

Sita deposited ₹ $5,000$ at 10\% simple interest for $2$ years. How much more money (In ₹) will Sita have in her account at the end of two years, if it is compounded semi-annually?

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