Select the correct match for the separation of anions using the given reagent.

  • A
    $CO_3^{2-}, SO_3^{2-} - BaCl_2$
  • B
    $CO_3^{2-}, HCO_3^{-} - CaCl_2$
  • C
    $SO_3^{2-}, SO_4^{2-} - (CH_3COO)_2Pb$
  • D
    $Cl^{-}, Br^{-} - AgNO_3$

Explore More

Similar Questions

$S^{2-}$ and $SO_3^{2-}$ can be distinguished by using

To a solution of a colourless efflorescent sodium salt,when dilute acid is added,a colourless gas is evolved along with the formation of a white precipitate. Acidified dichromate solution turns green when the colourless gas is passed through it. The sodium salt is

$H_2S$ gas is not evolved when $SO_3^{2-}$ ion reacts with the following reagents.

Given below are two statements:
Statement $I$: Griess-Ilosvay test is used for the detection of nitrite ion,which involves the use of sulphanilic acid and $\alpha$-naphthylamine reagent.
Statement $II$: In the above test,sulphanilic acid is diazotized by the acidified nitrite ion,which on further coupling with $\alpha$-naphthylamine forms an azo-dye.
In the light of the above statements,choose the correct answer from the options given below.

$A$ white precipitate was formed when $BaCl_{2}$ was added to the water extract of an inorganic salt. Further,a gas $X$ with a characteristic odour was released when the formed white precipitate was dissolved in dilute $HCl$. The anion present in the inorganic salt is ..... .

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo