Sam invested ₹ 15000 at 10 % per annum for on | vedclass

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Question

$A=P\left(1+\frac{R}{100}ight)^{N}$

$=15000\left(1+\frac{10}{200}ight)^{2}=15000\left(1+\frac{5}{100}ight)^{2}$

$=15000 	imes\left(\frac{

Vedclass · Accepted Answer

$16537.50$

Vedclass · Answer

$A=P\left(1+\frac{R}{100}ight)^{N}$

$=15000\left(1+\frac{10}{200}ight)^{2}=15000\left(1+\frac{5}{100}ight)^{2}$

$=15000 	imes\left(\frac{21}{20}ight)^{2}=\frac{15000 	imes 441}{400}$

$=37.5 	imes 441=₹ 16537.50$

Sam invested ₹ $15000$ at $10 \%$ per annum for one year. If the interest is compounded halfyearly, then the amount (In ₹) received by Sam at the end of the year will be

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