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Question

(C) In the process of glycolysis, Glucose is converted into Glucose$-6-$phosphate. Then, Glucose$-6-$phosphate is isomerized to Fructose$-6-$phosphate

Vedclass · Accepted Answer

$P - 	ext{Fructose-6-phosphate}, Q - 	ext{Fructose-1,6-bisphosphate}, R - 3	ext{-phosphoglyceraldehyde (PGAL)}, S - 1,3	ext{-bisphosphoglyceric acid (BPGA)}$

Vedclass · Answer

(C) In the process of glycolysis, Glucose is converted into Glucose$-6-$phosphate. Then, Glucose$-6-$phosphate is isomerized to Fructose$-6-$phosphate $(P)$. Fructose$-6-$phosphate is then phosphorylated to form Fructose$-1,6-$bisphosphate $(Q)$. Fructose$-1,6-$bisphosphate splits into two triose phosphates, one of which is $3-$phosphoglyceraldehyde $(R)$. $3$-phosphoglyceraldehyde is then oxidized to form $1,3-$bisphosphoglyceric acid $(S)$. Therefore, the correct sequence is $P = 	ext{Fructose-6-phosphate}$, $Q = 	ext{Fructose-1,6-bisphosphate}$, $R = 3	ext{-phosphoglyceraldehyde}$, and $S = 1,3	ext{-bisphosphoglyceric acid}$.

Refer to the figure and answer the question. Choose the correct names of $P$, $Q$, $R$, and $S$.

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