Reduction of nitrobenzene with zinc $(Zn)$ and ammonium chloride $(NH_4Cl)$ gives:

  • A
    Azobenzene
  • B
    Aniline
  • C
    Hydrazobenzene
  • D
    $N$-Phenylhydroxylamine

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The following sequence of reaction on $A$ gives:

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Identify $X$ and $Y$ in the following reactions:

$CH_3NH_2 + CHCl_3 + KOH \rightarrow$ Nitrogen containing compound $+ KCl + H_2O$. The nitrogen-containing compound is:

The correct order of basic strength is:

With respect to the following reaction,consider the given statements:
$C_6H_5NH_2 \xrightarrow{HNO_3, H_2SO_4, 288 \ K} \text{products}$
$(A)$ $o$-Nitroaniline and $p$-nitroaniline are the predominant products.
$(B)$ $p$-Nitroaniline and $m$-nitroaniline are the predominant products.
$(C)$ $HNO_3$ acts as an acid.
$(D)$ $H_2SO_4$ acts as an acid.

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