Ramkali saved ₹ 5 in the first week of a year | vedclass

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Question

(B) Given that the savings follow an Arithmetic Progression $(AP)$ where:First term $(a)$ = ₹ $5$Common difference $(d)$ = ₹ $1.75$$n$-th term $(a_n)$

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(B) Given that the savings follow an Arithmetic Progression $(AP)$ where:First term $(a)$ = ₹ $5$Common difference $(d)$ = ₹ $1.75$$n$-th term $(a_n)$ = ₹ $20.75$We use the formula for the $n$-th term of an $AP$: $a_n = a + (n - 1)d$Substituting the given values:$20.75 = 5 + (n - 1) 	imes 1.75$Subtract $5$ from both sides:$15.75 = (n - 1) 	imes 1.75$Divide both sides by $1.75$:$n - 1 = \frac{15.75}{1.75}$$n - 1 = 9$$n = 9 + 1 = 10$Thus,in the $10$-th week,her savings will be ₹ $20.75$.

Ramkali saved ₹ $5$ in the first week of a year and then increased her weekly savings by ₹ $1.75$. If in the $n$-th week,her weekly savings become ₹ $20.75$,find $n$.

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