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(A) Let the total amount invested be $x$.The interest from the first part is $12000 	imes 0.10 = 1200$.The remaining amount is $(x - 12000)$,which ea

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$20000$

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(A) Let the total amount invested be $x$.The interest from the first part is $12000 	imes 0.10 = 1200$.The remaining amount is $(x - 12000)$,which earns interest at $20 \%$,so the interest is $(x - 12000) 	imes 0.20$.The total interest earned is $14 \%$ of the total amount $x$,which is $0.14x$.Setting up the equation:$1200 + 0.20(x - 12000) = 0.14x$$1200 + 0.20x - 2400 = 0.14x$$0.20x - 0.14x = 2400 - 1200$$0.06x = 1200$$x = \frac{1200}{0.06} = 20000$Thus,the total amount invested is ₹ $20000$.

Peter invested an amount of ₹ $12,000$ at the rate of $10 \%$ $p.a.$ simple interest and another amount at the rate of $20 \%$ $p.a.$ simple interest. The total interest earned at the end of one year on the total amount invested became $14 \%$ $p.a.$ Find the total amount (in ₹) invested.

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