What are the oxidation states of both the chl | vedclass

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Question

(D) Bleaching powder is represented as $Ca(OCl)Cl$. It consists of a calcium ion $(Ca^{2+})$,a hypochlorite ion $(OCl^-)$,and a chloride ion $(Cl^-)$.

Vedclass · Accepted Answer

$+1, -1$

Vedclass · Answer

(D) Bleaching powder is represented as $Ca(OCl)Cl$. It consists of a calcium ion $(Ca^{2+})$,a hypochlorite ion $(OCl^-)$,and a chloride ion $(Cl^-)$. In the hypochlorite ion $(OCl^-)$,the oxygen atom has an oxidation state of $-2$. Let the oxidation state of chlorine be $x$. $x + (-2) = -1 \implies x = +1$. In the chloride ion $(Cl^-)$,the oxidation state of chlorine is $-1$. Therefore,the oxidation states of the two chlorine atoms are $+1$ and $-1$.

Compound	Oxidation number
$1$. $CrO_5$	$a$. $+6$
$2$. $H_2SO_4$	$b$. $+1$
$3$. $C_4OCl_2$	$c$. $-1$
$4$. $(CH_3)_2SO$	$d$. $+2$

What are the oxidation states of both the chlorine atoms in bleaching powder $(CaOCl_2)$?

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Match the following:
Compound Oxidation number
$1$. $CrO_5$ $a$. $+6$
$2$. $H_2SO_4$ $b$. $+1$
$3$. $C_4OCl_2$ $c$. $-1$
$4$. $(CH_3)_2SO$ $d$. $+2$

What is the oxidation number of $C$ in $C_3O_2$?

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