Number of common tangents of the ellipse  $\frac{{{{\left( {x - 2} \right)}^2}}}{9} + \frac{{{{\left( {y + 2} \right)}^2}}}{4} = 1$ and the circle $x^2 + y^2 -4x + 2y + 4 = 0$ is 

  • A

    $0$

  • B

    $1$

  • C

    $2$

  • D

    more than $2$

Similar Questions

Let $S = 0$ is an ellipse whose vartices are the extremities of minor axis of the ellipse $E:\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1,a > b$ If $S = 0$ passes through the foci of $E$ , then its eccentricity is (considering the eccentricity of $E$ as $e$ )

Consider the ellipse

$\frac{x^2}{4}+\frac{y^2}{3}=1$

Let $H (\alpha, 0), 0<\alpha<2$, be a point. A straight line drawn through $H$ parallel to the $y$-axis crosses the ellipse and its auxiliary circle at points $E$ and $F$ respectively, in the first quadrant. The tangent to the ellipse at the point $E$ intersects the positive $x$-axis at a point $G$. Suppose the straight line joining $F$ and the origin makes an angle $\phi$ with the positive $x$-axis.

$List-I$ $List-II$
If $\phi=\frac{\pi}{4}$, then the area of the triangle $F G H$ is ($P$) $\frac{(\sqrt{3}-1)^4}{8}$
If $\phi=\frac{\pi}{3}$, then the area of the triangle $F G H$ is ($Q$) $1$
If $\phi=\frac{\pi}{6}$, then the area of the triangle $F G H$ is ($R$) $\frac{3}{4}$
If $\phi=\frac{\pi}{12}$, then the area of the triangle $F G H$ is ($S$) $\frac{1}{2 \sqrt{3}}$
  ($T$) $\frac{3 \sqrt{3}}{2}$

The correct option is:

  • [IIT 2022]

The equations of the directrices of the ellipse $16{x^2} + 25{y^2} = 400$ are

Tangents are drawn from points onthe circle $x^2 + y^2 = 49$ to the ellipse $\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{24}} = 1$ angle between the tangents is

Equation of the ellipse whose axes are the axes of coordinates and which passes through the point  $(-3,1) $ and has eccentricity $\sqrt {\frac{2}{5}} $ is 

  • [AIEEE 2011]