Measure of two quantities along with the prec | vedclass

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Question

Error in $AB$

$=\pm\left(\frac{\Delta \mathrm{A}}{\mathrm{A}}+\frac{\Delta \mathrm{B}}{\mathrm{B}}\right) \mathrm{AB}=\pm\left[\frac{0.5}{2.5}+\fra

Vedclass · Accepted Answer

$\left( {0.25 \pm 0.08} \right)\,m$

Vedclass · Answer

Error in $AB$

$=\pm\left(\frac{\Delta \mathrm{A}}{\mathrm{A}}+\frac{\Delta \mathrm{B}}{\mathrm{B}}\right) \mathrm{AB}=\pm\left[\frac{0.5}{2.5}+\frac{0.01}{0.10}\right][0.25]$

$=\pm 0.075=\pm 0.08$

Therefore $A B=(0.25 \pm 0.08) m$

Measure of two quantities along with the precision of respective measuring instrument $A = 2.5\,m{s^{ - 1}} \pm 0.5\,m{s^{ - 1}}$, $B = 0.10\,s \pm 0.01\,s$ The value of $AB$ will be

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