Mean and variance of a binomial probability distribution are $4$ and $\frac{4}{3}$ respectively. Then the probability of at least two successes is equal to:

  • A
    $\frac{552}{729}$
  • B
    $\frac{201}{243}$
  • C
    $\frac{298}{343}$
  • D
    $\frac{716}{729}$

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