Match List-I with List-II and select the corr | vedclass

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(B) We analyze each unit in List-$I$:$1$. Joule $(J)$: Unit of energy. Since $W = Q 	imes V$,$1 	ext{ Joule} = 1 	ext{ Coulomb} 	imes 1 	ext{ Vol

Vedclass · Accepted Answer

$I-C, II-F, III-A, IV-B$

Vedclass · Answer

(B) We analyze each unit in List-$I$:$1$. Joule $(J)$: Unit of energy. Since $W = Q 	imes V$,$1 	ext{ Joule} = 1 	ext{ Coulomb} 	imes 1 	ext{ Volt}$. Thus,$I-C$.$2$. Watt $(W)$: Unit of power. Since $P = I^2 R$,$1 	ext{ Watt} = 1 	ext{ Amp}^2 	imes 1 	ext{ Ohm}$. Thus,$II-F$.$3$. Volt $(V)$: Unit of potential difference. From Faraday's law,$V = L \frac{di}{dt}$,so $1 	ext{ Volt} = 1 	ext{ Henry} 	imes 1 	ext{ Amp/sec}$. Thus,$III-A$.$4$. Coulomb $(C)$: Unit of charge. Since $Q = C 	imes V$ (where $C$ is capacitance),$1 	ext{ Coulomb} = 1 	ext{ Farad} 	imes 1 	ext{ Volt}$. Thus,$IV-B$.Therefore,the correct matching is $I-C, II-F, III-A, IV-B$.

List-$I$	List-$II$
$I$. Joule	$A$. $\text{Henry} \times \text{Amp/sec}$
$II$. Watt	$B$. $\text{Farad} \times \text{Volt}$
$III$. Volt	$C$. $\text{Coulomb} \times \text{Volt}$
$IV$. Coulomb	$D$. $\text{Oersted} \times \text{cm}$
	$E$. $\text{Amp} \times \text{Gauss}$
	$F$. $\text{Amp}^2 \times \text{Ohm}$

Column-$I$	Column-$II$
$(A)$ Electrical resistance	$(P)$ $M^1 L^3 T^{-3} A^{-2}$
$(B)$ Electrical potential	$(Q)$ $M^1 L^2 T^{-3} A^{-2}$
$(C)$ Specific resistance	$(R)$ $M^1 L^2 T^{-3} A^{-1}$
$(D)$ Specific conductance	$(S)$ None of these

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Match the following two columns:
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$(A)$ Electrical resistance $(P)$ $M^1 L^3 T^{-3} A^{-2}$
$(B)$ Electrical potential $(Q)$ $M^1 L^2 T^{-3} A^{-2}$
$(C)$ Specific resistance $(R)$ $M^1 L^2 T^{-3} A^{-1}$
$(D)$ Specific conductance $(S)$ None of these

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