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(A) The reagent $Br_2 + H_2O$ (bromine water) is used to test for unsaturation (alkenes and alkynes). Compounds containing double or triple bonds will

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$Al_4C_3 + H_2O \rightarrow CH_4$

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(A) The reagent $Br_2 + H_2O$ (bromine water) is used to test for unsaturation (alkenes and alkynes). Compounds containing double or triple bonds will decolorize the reddish-brown color of bromine water.$1$. $Al_4C_3 + 12H_2O \rightarrow 3CH_4 + 4Al(OH)_3$. Methane $(CH_4)$ is a saturated alkane and does not react with bromine water.$2$. $Mg_2C_3 + 4H_2O \rightarrow CH_3-C \equiv CH + 2Mg(OH)_2$. Propyne is an alkyne and will decolorize bromine water.$3$. $CaC_2 + 2H_2O \rightarrow HC \equiv CH + Ca(OH)_2$. Ethyne is an alkyne and will decolorize bromine water.$4$. $Ag_2C_2$ is a metal acetylide that is generally insoluble and does not undergo simple hydrolysis to yield an unsaturated hydrocarbon product in this context.Comparing the options,$Al_4C_3$ produces methane,which is saturated and will not decolorize bromine water.

The major product of which of the following reactions will not decolorize $Br_2 + H_2O$?

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