The major product obtained in the following reaction is:

  • A
    $1-$($4$-nitrophenyl)$-2-$bromoethane
  • B
    $1-$($4$-nitrophenyl)$-1-$bromoethane
  • C
    $1-$bromo$-1-$ethyl$-4-$nitrobenzene
  • D
    $1-$bromo$-2-$ethyl$-4-$nitrobenzene

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For the reactions given below:
$(I)$ Cyclohexyl chloride $\rightarrow$ Cyclohexyl cation + $Cl^-$,$\Delta H_1^{\circ}$
$(II)$ Cyclohex$-2-$enyl chloride $\rightarrow$ Cyclohex$-2-$enyl cation + $Cl^-$,$\Delta H_2^{\circ}$
$(III)$ Benzyl chloride $\rightarrow$ Benzyl cation + $Cl^-$,$\Delta H_3^{\circ}$
$(IV)$ Chlorobenzene $\rightarrow$ Phenyl cation + $Cl^-$,$\Delta H_4^{\circ}$
The correct decreasing order of enthalpies of reaction for producing the carbocation is:

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What is the product of the reaction given below?

The relative reactivity of the following halides toward $S_{N}2$ reaction follows the order:
$(P)$ $CH_2=CH-Cl$
$(Q)$ $CH_3-CH_2-Cl$
$(R)$ $CH_3-O-CH_2-CH_2-Cl$
$(S)$ $C_6H_5-CH_2-Cl$

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From the given pairs of compounds,in which will the first compound undergo $S_N2$ reaction faster?

Which of the following will undergo $S_{N}2$ reaction most rapidly?

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