The major product of the reaction is:

  • A
    tert-butylbenzene
    Option A
  • B
    neopentylbenzene
    Option B
  • C
    $1,1-$dimethyl$-2-$phenylethane
    Option C
  • D
    isobutylbenzene
    Option D

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Observe the following statements regarding $C_{60}$.
$i$. All carbons are $sp^2$-hybridised.
$ii$. It contains $12$ rings of five carbons each and $20$ rings of six carbons each.
$iii$. It is a non-aromatic compound.
$iv$. It is a pure form of carbon.
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$\text{Benzene} + Cl_{2(\text{excess})} \xrightarrow{AlCl_3, \Delta} X$

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