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(C) The emissive power of the black body at temperature $T = 400\, K$ is given by the Stefan-Boltzmann law: $E = \sigma T^4$.Substituting the values:

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The black body will appear brighter than the furnace

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(C) The emissive power of the black body at temperature $T = 400\, K$ is given by the Stefan-Boltzmann law: $E = \sigma T^4$.Substituting the values: $E = 5.67 	imes 10^{-8} 	imes (400)^4$.$E = 5.67 	imes 10^{-8} 	imes 2.56 	imes 10^{10} = 5.67 	imes 256 = 1451.52\, W/m^2$.However,the intensity of the incident sunlight is $I = 2000\, W/m^2$.Since the incident intensity $I$ is greater than the emissive power $E$ of the black body at $400\, K$,the black body will absorb more energy from the sunlight than it emits at its current temperature.In the steady state,the black body will reach a higher temperature than the furnace to balance the energy,making it appear brighter than the furnace.

Inside a closed furnace held at a temperature of $400\, K,$ we have a black body. $A$ hole of area $10\, cm^2$ is opened in the furnace so that sunlight starts falling on the black body. The intensity of sunlight is $2000\, W/m^2.$ In the steady state:

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