In the reaction CH_3-CH=CH_2 + H_2O + [O] xri | vedclass

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(B) The reaction involves the oxidation of propene to propane-$1,2$-diol,followed by oxidative cleavage.The cleavage of propane-$1,2$-diol $(CH_3-CH(O

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$CH_3-COOH$

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(B) The reaction involves the oxidation of propene to propane-$1,2$-diol,followed by oxidative cleavage.The cleavage of propane-$1,2$-diol $(CH_3-CH(OH)-CH_2(OH))$ using an oxidizing agent leads to the breaking of the $C-C$ bond between the two hydroxyl-bearing carbons.This process yields ethanoic acid $(CH_3COOH)$ and methanoic acid $(HCOOH)$.Therefore,$X$ is $CH_3COOH$.

In the reaction $CH_3-CH=CH_2 + H_2O + [O]$ $\xrightarrow[Acid]{KMnO_4} CH_3-CH(OH)-CH_2(OH)$ $\xrightarrow{[O]} X + HCOOH$,$X$ is:

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