In the reaction Ar-OH + RX xrightarrow{text{a | vedclass

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(C) The reaction between a phenol $(Ar-OH)$ and an alkyl halide $(RX)$ in the presence of an alkali (like $NaOH$) is known as the Williamson ether syn

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An ether

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(C) The reaction between a phenol $(Ar-OH)$ and an alkyl halide $(RX)$ in the presence of an alkali (like $NaOH$) is known as the Williamson ether synthesis. In this reaction,the alkali converts the phenol into a phenoxide ion $(Ar-O^-)$,which then acts as a nucleophile and attacks the alkyl halide $(RX)$ via an $S_N2$ mechanism to form an alkyl aryl ether $(Ar-O-R)$. Therefore,the product $A$ is an ether.

In the reaction $Ar-OH + RX \xrightarrow{\text{alkali}} A$,$A$ is

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