In the Maxwell-Boltzmann distribution of mole | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The most probable speed $(U_{M.P.})$ is given by the formula $U_{M.P.} = \sqrt{\frac{2RT}{M}}$.From this expression,it is clear that $U_{M.P.} \pr

Vedclass · Accepted Answer

$U_{M.P.}$ at $T_2 > U_{M.P.}$ at $T_1$

Vedclass · Answer

(B) The most probable speed $(U_{M.P.})$ is given by the formula $U_{M.P.} = \sqrt{\frac{2RT}{M}}$.From this expression,it is clear that $U_{M.P.} \propto \sqrt{T}$.As the temperature increases,the peak of the Maxwell-Boltzmann distribution curve shifts to the right,indicating a higher most probable speed.In the given graph,the peak for $T_2$ is at a higher velocity value compared to the peak for $T_1$,which implies $T_2 > T_1$.Therefore,$U_{M.P.}$ at $T_2 > U_{M.P.}$ at $T_1$.

In the Maxwell-Boltzmann distribution of molecular speeds shown below,which of the following is correct regarding the most probable speed $(U_{M.P.})$ at temperatures $T_1$ and $T_2$?

Similar Questions

The ratio of the most probable speed,average speed,and $RMS$ speed is given by:

At $300 \ K$ the average velocity of a gas is $3 \times 10^2 \ cm / s$. The average velocity (in $cm / s$) of it at $1200 \ K$ is

The ratio of most probable velocity to that of average velocity is

The volumes of ozone and chlorine gas diffusing in the same time are $35 \ mL$ and $29 \ mL$ respectively. If the molar mass of chlorine is $71$,calculate the molar mass of ozone. (in $.7$)

The ratio of the rates of diffusion of $SO_2$,$O_2$,and $CH_4$ is.....

Vedclass Test Series

Exam Paper Generator

Online Exam Module