In the following reaction: $CH_3-CH_2-CH(OH)-CH_3 \xrightarrow[475 \ K]{H_2SO_4}$
- A$CH_3-CH=CH-CH_3$ predominates
- B$CH_2=CH-CH_2-CH_3$ predominates
- CBoth are formed in equal amounts
- DThe amount of production depends on the nature of catalyst
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