In the following reaction
$C_6H_5CH_2Br \xrightarrow[{(ii)H_3O^{+}}]{{(i)Mg, \text{Ether}}} X$
Product $X$ is

  • A
    $C_6H_5CH_3$
  • B
    $C_6H_5CH_2OH$
  • C
    $C_6H_5CH_2CH_2C_6H_5$
  • D
    $C_6H_5CH_2OCH_2C_6H_5$

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