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(A) For equation $I$:$(625)^{\frac{1}{4}} x + \sqrt{1225} = 155$Since $625 = 5^4$,we have $(5^4)^{\frac{1}{4}} x + 35 = 155$$5x + 35 = 155$$5x = 155 -

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$x > y$

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(A) For equation $I$:$(625)^{\frac{1}{4}} x + \sqrt{1225} = 155$Since $625 = 5^4$,we have $(5^4)^{\frac{1}{4}} x + 35 = 155$$5x + 35 = 155$$5x = 155 - 35 = 120$$x = \frac{120}{5} = 24$For equation $II$:$\sqrt{196} y + 13 = 279$Since $\sqrt{196} = 14$,we have $14y + 13 = 279$$14y = 279 - 13 = 266$$y = \frac{266}{14} = 19$Comparing the values,$x = 24$ and $y = 19$.Therefore,$x > y$.

In the following questions,two equations numbered $I$ and $II$ are given. You have to solve both the equations and give the answer.
$I$: $(625)^{\frac{1}{4}} x + \sqrt{1225} = 155$
$II$: $\sqrt{196} y + 13 = 279$

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In the following questions,two equations numbered $I$ and $II$ are given. You have to solve both the equations and give the answer.$I$: $(625)^{\frac{1}{4}} x + \sqrt{1225} = 155$$II$: $\sqrt{196} y + 13 = 279$