In the equilibrium HClO_4 + H_2O rightlefthar | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the Brønsted-Lowry theory,an acid-base pair differs by a single proton $(H^+)$. In the reaction $HClO_4 + H_2O \rightleftharpoons H_3

Vedclass · Accepted Answer

$ClO_4^-$ is the conjugate base of $HClO_4$

Vedclass · Answer

(D) According to the Brønsted-Lowry theory,an acid-base pair differs by a single proton $(H^+)$. In the reaction $HClO_4 + H_2O \rightleftharpoons H_3O^{+} + ClO_4^-$,$HClO_4$ acts as an acid and loses a proton to form its conjugate base,$ClO_4^-$. Similarly,$H_2O$ acts as a base and gains a proton to form its conjugate acid,$H_3O^{+}$. Therefore,$ClO_4^-$ is the conjugate base of $HClO_4$.

List-$I$ (Acid)	List-$II$ ($K_a$ - Ionization Constant)
$A$. $HCN$	$I$. $6.8 \times 10^{-4}$
$B$. $H_2C_2O_4$	$II$. $8.9 \times 10^{-8}$
$C$. $H_2S$	$III$. $4.9 \times 10^{-10}$
$D$. Niacin	$IV$. $5.6 \times 10^{-2}$
	$V$. $1.5 \times 10^{-5}$

In the equilibrium $HClO_4 + H_2O \rightleftharpoons H_3O^{+} + ClO_4^-$,which of the following statements is correct?

Similar Questions

What is the conjugate base of $OH^{-}$?

The conjugate base of $HCO_3^-$ is

Conjugate acid and conjugate base of $HCO_3^{-}$ are respectively

$H^{+}$ is a

Match the following:

List-$I$ (Acid) List-$II$ ($K_a$ - Ionization Constant)

$A$. $HCN$ $I$. $6.8 \times 10^{-4}$

$B$. $H_2C_2O_4$ $II$. $8.9 \times 10^{-8}$

$C$. $H_2S$ $III$. $4.9 \times 10^{-10}$

$D$. Niacin $IV$. $5.6 \times 10^{-2}$

$V$. $1.5 \times 10^{-5}$

The correct match is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module