In the above chemical reaction sequence,"$A$" and "$B$" respectively are:

  • A
    $O_3, Zn / H_2O$ and $NaOH_{(aq)} / I_2$
  • B
    $H_2O, H^+$ and $NaOH_{(aq)} / I_2$
  • C
    $H_2O, H^+$ and $KMnO_4$
  • D
    $O_3, Zn / H_2O$ and $KMnO_4$

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$H_2C=CH-CH_2-CH_2-CH(OH)-CH_3$ $\xrightarrow[\text{Pyridine}]{SOCl_2} (A)$ $\xrightarrow[H_2O]{O_3/Zn} (B) (C_5H_9ClO)$ $\xrightarrow{NaBH_4} (C)$
Compound $(C)$ is:

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Consider all possible isomeric ketones,including stereoisomers of $MW = 100$. All these isomers are independently reacted with $NaBH_4$ ($NOTE$: stereoisomers are also reacted separately). The total number of ketones that give a racemic product$(s)$ is/are

In the reaction,the acid obtained will be
$CH_3CHO + HCN \to CH_3CH(OH)CN \xrightarrow{H_2O} CH_3CH(OH)COOH$

Identify the product $P$ from the following sequence of reactions?

The structure of $(B)$ is

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