In the ground state of He^{+} ion,how much en | vedclass

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(A) The energy required is the difference between the energy level of the $n=4$ state and the ground state $(n=1)$.The formula for energy difference i

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$51$

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(A) The energy required is the difference between the energy level of the $n=4$ state and the ground state $(n=1)$.The formula for energy difference is: $E = 13.6 	imes Z^2 	imes (\frac{1}{n_1^2} - \frac{1}{n_2^2}) \ eV$.For $He^{+}$,$Z = 2$. The ground state is $n_1 = 1$. The second line of the Balmer series corresponds to a transition from $n=4$ to $n=2$,so the electron must be excited to the $n=4$ state.$E = 13.6 	imes 2^2 	imes (\frac{1}{1^2} - \frac{1}{4^2}) \ eV$$E = 13.6 	imes 4 	imes (1 - \frac{1}{16}) \ eV$$E = 54.4 	imes (\frac{15}{16}) \ eV$$E = 51 \ eV$.

In the ground state of $He^{+}$ ion,how much energy must be supplied to the electron so that the second line of the Balmer series is obtained in its spectrum? ................. $eV$

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