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(C) The fringe width $\beta$ in a Young's double-slit experiment is given by the formula: $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelen

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$2D$

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(C) The fringe width $\beta$ in a Young's double-slit experiment is given by the formula: $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the slits and the screen,and $d$ is the separation between the two slits.Given that the fringe width $\beta$ remains constant,we have $\frac{\lambda D}{d} = 	ext{constant}$.If the slit separation $d$ is doubled $(d' = 2d)$,let the new distance be $D'$.Then,$\frac{\lambda D}{d} = \frac{\lambda D'}{2d}$.Solving for $D'$,we get $D' = 2D$.Therefore,the distance of the screen from the slits should be doubled.

In a Young's double-slit experiment,the separation of the two slits is doubled. To keep the same spacing of fringes,the distance $D$ of the screen from the slits should be made

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