In a balanced Wheatstone's network,the resist | vedclass

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(A) In a balanced Wheatstone's network,the condition is given by $\frac{P}{Q} = \frac{R}{S}$.If the resistances in arms $Q$ and $S$ are interchanged,t

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Network is not balanced

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(A) In a balanced Wheatstone's network,the condition is given by $\frac{P}{Q} = \frac{R}{S}$.If the resistances in arms $Q$ and $S$ are interchanged,the new ratio becomes $\frac{P}{S}$ and $\frac{R}{Q}$.For the network to remain balanced,we would require $\frac{P}{S} = \frac{R}{Q}$,which implies $PQ = RS$. This is generally not true unless $Q = S$.Therefore,the condition $\frac{P}{Q} = \frac{R}{S}$ is no longer satisfied,and the network is not balanced.

In a balanced Wheatstone's network,the resistances in the arms $Q$ and $S$ are interchanged. As a result of this:

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