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(A) According to Newton's Law of Gravitation,the force $F$ between two bodies of masses $m_1$ and $m_2$ separated by a distance $r$ is given by $F = G

Vedclass · Accepted Answer

It remains the same.

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(A) According to Newton's Law of Gravitation,the force $F$ between two bodies of masses $m_1$ and $m_2$ separated by a distance $r$ is given by $F = G \frac{m_1 m_2}{r^2}$.Given that the new masses are $m_1' = 2m_1$ and $m_2' = 2m_2$,and the new distance is $r' = 2r$.The new gravitational force $F'$ is given by $F' = G \frac{m_1' m_2'}{(r')^2}$.Substituting the new values: $F' = G \frac{(2m_1)(2m_2)}{(2r)^2} = G \frac{4 m_1 m_2}{4 r^2}$.Simplifying the expression: $F' = G \frac{m_1 m_2}{r^2} = F$.Therefore,the new gravitational force remains the same.

If the mass of two bodies is doubled and the distance between them is also doubled,what happens to the new gravitational force?

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