If the amount obtained by Mahesh by investing | vedclass

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(A) Let the sum invested by Mahesh be $P_1 = ₹ 1500$,rate $R_1 = 8 \%$,and time $T_1 = 2.5$ years.The amount $A_1$ obtained by Mahesh is $P_1 + 	ext{

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₹ $1636 \frac{4}{11}$

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(A) Let the sum invested by Mahesh be $P_1 = ₹ 1500$,rate $R_1 = 8 \%$,and time $T_1 = 2.5$ years.The amount $A_1$ obtained by Mahesh is $P_1 + 	ext{Simple Interest} = P_1(1 + \frac{R_1 T_1}{100})$.$A_1 = 1500(1 + \frac{8 	imes 2.5}{100}) = 1500(1 + \frac{20}{100}) = 1500(1.2) = ₹ 1800$.Let the sum invested by Suresh be $P_2 = x$,rate $R_2 = 5 \%$,and time $T_2 = 2$ years.The amount $A_2$ obtained by Suresh is $P_2(1 + \frac{R_2 T_2}{100})$.$A_2 = x(1 + \frac{5 	imes 2}{100}) = x(1 + \frac{10}{100}) = x(1.1) = 1.1x$.Since $A_1 = A_2$,we have $1800 = 1.1x$.$x = \frac{1800}{1.1} = \frac{18000}{11} = 1636 \frac{4}{11}$.Thus,the sum invested by Suresh is ₹ $1636 \frac{4}{11}$.

If the amount obtained by Mahesh by investing ₹ $1500$ for $2 \frac{1}{2}$ years at the rate of $8 \%$ $p.a.$ is equal to the amount obtained by Suresh by investing a certain sum for $2$ years at $5 \%$ $p.a.$ simple interest,then the sum invested by Suresh is

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