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(B) Let $\overrightarrow{a}$ and $\overrightarrow{b}$ be two unit vectors,so $|\overrightarrow{a}| = |\overrightarrow{b}| = 1$. Let $	heta$ be the an

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$\left(\frac{\pi}{3}, \frac{\pi}{2}\right)$

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(B) Let $\overrightarrow{a}$ and $\overrightarrow{b}$ be two unit vectors,so $|\overrightarrow{a}| = |\overrightarrow{b}| = 1$. Let $	heta$ be the angle between them.The magnitude of their sum is $|\overrightarrow{a} + \overrightarrow{b}| = \sqrt{1^2 + 1^2 + 2(1)(1)\cos 	heta} = \sqrt{2 + 2\cos 	heta} = 2\cos(	heta/2)$.The magnitude of their difference is $|\overrightarrow{a} - \overrightarrow{b}| = \sqrt{1^2 + 1^2 - 2(1)(1)\cos 	heta} = \sqrt{2 - 2\cos 	heta} = 2\sin(	heta/2)$.Given the condition: $|\overrightarrow{a} - \overrightarrow{b}| First part: $|\overrightarrow{a} - \overrightarrow{b}| Second part: $|\overrightarrow{a} + \overrightarrow{b}|  1/\sqrt{3} \Rightarrow 	heta/2 > \pi/6 \Rightarrow 	heta > \pi/3$.Combining these,we get $	heta \in \left(\frac{\pi}{3}, \frac{\pi}{2}ight)$.

If the magnitude of the sum of two unit vectors is greater than the magnitude of their difference and less than $\sqrt{3}$ times the magnitude of their difference,then the complete set of values for the angle $\theta$ between the vectors is

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