If x propto {t^{5/2}} , then | vedclass

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Question

Given $x \propto t^2 \quad \Rightarrow x= Kt ^2 \quad$ where $K = constant$

$	herefore$ Velocity of the particle $v =\frac{ dx }{ dt }=2 Kt$

$\

Vedclass · Accepted Answer

both$ (A)$ and $(B)$

Vedclass · Answer

Given $x \propto t^2 \quad \Rightarrow x= Kt ^2 \quad$ where $K = constant$

$	herefore$ Velocity of the particle $v =\frac{ dx }{ dt }=2 Kt$

$	herefore$ Acceleration of the particle $a =\frac{ dv }{ dt }=2 K = constant$

If $x \propto {t^{5/2}}$ , then

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