Identify the type of the following polynomial | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To identify the type of polynomial,we first simplify the expression $p(x) = (x - 15)(x + 15)$.Using the algebraic identity $(a - b)(a + b) = a^2 -

Vedclass · Accepted Answer

quadratic

Vedclass · Answer

(B) To identify the type of polynomial,we first simplify the expression $p(x) = (x - 15)(x + 15)$.Using the algebraic identity $(a - b)(a + b) = a^2 - b^2$,we get:$p(x) = x^2 - 15^2$$p(x) = x^2 - 225$The highest power (degree) of the variable $x$ in this polynomial is $2$.$A$ polynomial with a degree of $2$ is called a quadratic polynomial.Therefore,the correct option is $B$.

Identify the type of the following polynomial based on its degree: $p(x) = (x - 15)(x + 15)$

Similar Questions

The zeroes of the quadratic polynomial $x^{2}+99x+127$ are

The graph of $p(x) = x^{2} + 6x + 9$ intersects the $X$-axis $\ldots \ldots \ldots \ldots$

Divide : $3x^{2} - x^{3} - 3x + 5$ by $x - 1 - x^{2}$.

Are the following statements 'True' or 'False'? Justify your answers.
The only value of $k$ for which the quadratic polynomial $k x^{2}+x+k$ has equal zeros is $\frac{1}{2}$.

Prove that $1/2, 1$ and $-2$ are the zeros of the cubic polynomial $p(x) = 2x^3 + x^2 - 5x + 2$. Also,verify the relationship between the zeros and the coefficients.

Vedclass Test Series

Exam Paper Generator

Online Exam Module