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(A) In a $bcc$ (body-centered cubic) lattice,the central atom is surrounded by $8$ nearest neighbours located at the corners of the cube.These $8$ ato

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$8, 6$

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(A) In a $bcc$ (body-centered cubic) lattice,the central atom is surrounded by $8$ nearest neighbours located at the corners of the cube.These $8$ atoms are at a distance of $\frac{\sqrt{3}}{2}a$,where $a$ is the edge length of the unit cell.The next nearest neighbours are the atoms located at the centers of the adjacent unit cells,which correspond to the corners of the original cube.There are $6$ such atoms located at a distance of $a$ from the reference atom.Therefore,the number of nearest and next nearest neighbours are $8$ and $6$,respectively.

How many "nearest" and "next nearest" neighbours,respectively,does potassium have in a $bcc$ lattice?

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