How is heavy water prepared? Compare its physical properties with those of ordinary water.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Heavy water $(D_{2}O)$ is prepared by the prolonged electrolysis of ordinary water $(H_{2}O)$. Since $H_{2}O$ is electrolyzed faster than $D_{2}O$,the remaining water becomes enriched in $D_{2}O$.
The physical properties of $H_{2}O$ and $D_{2}O$ are compared in the table below:
Property $H_{2}O$ $D_{2}O$
Molecular mass $(g \ mol^{-1})$ $18.0151$ $20.0276$
Melting point $(K)$ $273.0$ $276.8$
Boiling point $(K)$ $373.0$ $374.4$
Enthalpy of formation $(kJ \ mol^{-1})$ $-285.9$ $-294.6$
Enthalpy of vaporisation at $373 \ K$ $(kJ \ mol^{-1})$ $40.66$ $41.61$
Enthalpy of fusion $(kJ \ mol^{-1})$ $6.01$ $6.28$
Temperature of max. density $(K)$ $276.98$ $284.2$
Density at $298 \ K$ $(g \ cm^{-3})$ $1.0000$ $1.1059$
Viscosity (centipoise) $0.8903$ $1.107$
Dielectric constant $(C^{2} / Nm^{2})$ $78.39$ $78.06$
Electrical conductivity at $298 \ K$ $(ohm^{-1} \ cm^{-1})$ $5.7 \times 10^{-8}$ $3.0 \times 10^{-8}$

Explore More

Similar Questions

Oxygen is slightly denser than air,so it is collected over:

The decreasing order of hydrogen bonding in the following forms of water is correctly represented by:
$A.$ Liquid water
$B.$ Ice
$C.$ Impure water

Assertion $(A)$ : $NaCl$ is less soluble in heavy water than in ordinary water.
Reason $(R)$ : Dielectric constant of ordinary water is more than that of heavy water.
The correct answer is

The density of water is greater than that of ice because of

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo