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(C) The reaction is a Friedel-Crafts acylation of $N$-phenylbenzamide (benzanilide) with acetyl chloride $(CH_3COCl)$ in the presence of $AlCl_3$. In

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(C) The reaction is a Friedel-Crafts acylation of $N$-phenylbenzamide (benzanilide) with acetyl chloride $(CH_3COCl)$ in the presence of $AlCl_3$. In $N$-phenylbenzamide,the nitrogen atom is attached to two phenyl rings: one from the aniline part and one from the benzoyl part. The $-NHCO-$ group is an ortho/para-directing group because of the lone pair on the nitrogen atom,which increases the electron density on the aniline ring. However,the benzoyl group attached to the nitrogen is strongly electron-withdrawing,which deactivates the benzoyl ring towards electrophilic substitution. Therefore,the electrophilic substitution (Friedel-Crafts acylation) occurs on the more electron-rich aniline ring at the para position due to steric hindrance at the ortho position. Thus,the major product is $N-(4-acetylphenyl)benzamide$.

Give the major product of the following reaction $.$

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