Give rules for writing resonance structures.
(N/A) $(i)$ The resonance structures must have the same positions of nuclei,i.e.,the atomic framework remains constant.
$(ii)$ The resonance structures must have the same number of unpaired electrons.
$(iii)$ Among the resonance structures,the one which has a greater number of covalent bonds,all atoms with a complete octet of electrons,less separation of opposite charges,and more dispersal of charge is more stable than others.
$(ii)$ The resonance structures must have the same number of unpaired electrons.
$(iii)$ Among the resonance structures,the one which has a greater number of covalent bonds,all atoms with a complete octet of electrons,less separation of opposite charges,and more dispersal of charge is more stable than others.
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Similar Questions
Examine the following resonating structures of formic acid for their individual stability and then answer the question given below.
$(I)$ $H-COOH$
$(II)$ $H-C(OH)=O^+$
$(III)$ $H-C^+(OH)-O^-$
$(IV)$ $H-C^-(OH)-O^+$
Which of the following arrangements gives the correct order of decreasing stability of the above-mentioned resonance contributors?
$(I)$ $H-COOH$
$(II)$ $H-C(OH)=O^+$
$(III)$ $H-C^+(OH)-O^-$
$(IV)$ $H-C^-(OH)-O^+$
Which of the following arrangements gives the correct order of decreasing stability of the above-mentioned resonance contributors?
Difficult
View SolutionResonance in $X_2Y$ can be represented as shown in the image. The enthalpy of formation of $X_2Y$ $(X \equiv X(g) + \frac{1}{2} Y = Y(g) \rightarrow X_2Y(g))$ is $80 \ kJ \ mol^{-1}$. The magnitude of resonance energy of $X_2Y$ is $......... \ kJ \ mol^{-1}$ (nearest integer value). Given: Bond energies of $X \equiv X, X=X, Y=Y$ and $X=Y$ are $940, 410, 500$ and $602 \ kJ \ mol^{-1}$ respectively. Valence $X: 3, Y: 2$.
Assertion : Energy of resonance hybrid is equal to the average of energies of all canonical forms.
Reason : Resonance hybrid cannot be presented by a single structure.
Reason : Resonance hybrid cannot be presented by a single structure.
DifficultAIIMS 2016
View SolutionWhich of the following molecules shows the least resonance stabilization?
DifficultJEE MAIN 2017
View SolutionThe $C - C$ bond length in benzene lies between a single and a double bond. The reason is:
Easy
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