The geometry,hybridization,and magnetic momen | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $CN^-$ is a strong field ligand,while $Br^-$ and $F^-$ are weak field ligands.For $[Ni(CN)_4]^{2-}$,$Ni^{2+}$ has $d^8$ configuration. $CN^-$ caus

Vedclass · Accepted Answer

Square planar,tetrahedral,octahedral : $dsp^2, sp^3, sp^3d^2 : 0, 5.9, 4.9$

Vedclass · Answer

(D) $CN^-$ is a strong field ligand,while $Br^-$ and $F^-$ are weak field ligands.For $[Ni(CN)_4]^{2-}$,$Ni^{2+}$ has $d^8$ configuration. $CN^-$ causes pairing,leading to $dsp^2$ hybridization (square planar) with $0$ unpaired electrons and $\mu = 0 \ BM$.For $[MnBr_4]^{2-}$,$Mn^{2+}$ has $d^5$ configuration. $Br^-$ is a weak ligand,leading to $sp^3$ hybridization (tetrahedral) with $5$ unpaired electrons and $\mu = \sqrt{5(5+2)} = 5.9 \ BM$.For $[FeF_6]^{4-}$,$Fe^{2+}$ has $d^6$ configuration. $F^-$ is a weak ligand,leading to $sp^3d^2$ hybridization (octahedral) with $4$ unpaired electrons and $\mu = \sqrt{4(4+2)} = 4.9 \ BM$.

The geometry,hybridization,and magnetic moment of the ions $[Ni(CN)_4]^{2-}$,$[MnBr_4]^{2-}$,and $[FeF_6]^{4-}$ respectively are:

Similar Questions

$[Cu(NH_3)_4]^{2+}$ shows the following hybridization:

The geometry of $[Ni(CO)_4]$ and $[NiCl_2(PPh_3)_2]$ are

Which of the following has $dsp^2$ hybridization?

Consider the transition metal ions $Mn^{3+}$,$Cr^{3+}$,$Fe^{3+}$,and $Co^{3+}$. All form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective $d$-orbitals of the complexes is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module