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(C) metal with a more negative standard reduction potential is a stronger reducing agent and can displace a metal with a more positive reduction poten

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$Ag$

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(C) metal with a more negative standard reduction potential is a stronger reducing agent and can displace a metal with a more positive reduction potential from its salt solution.The given standard reduction potentials are:$E^o Zn^{2+}/Zn = -0.76 \ V$$E^o Co^{2+}/Co = -0.28 \ V$$E^o Cu^{2+}/Cu = +0.34 \ V$$E^o Ag^+/Ag = +0.80 \ V$Comparing these values,$Ag^+$ has the highest positive reduction potential $(+0.80 \ V)$,meaning $Ag$ is the weakest reducing agent and can be displaced by all other metals $(Zn, Co, Cu)$ from their respective solutions.Therefore,the correct answer is $Ag$.

Based on the given standard electrode potentials,identify the metal that can be displaced from its salt solution by all other metals listed.
$E^o Zn^{2+}/Zn = -0.76 \ V, E^o Cu^{2+}/Cu = +0.34 \ V$
$E^o Ag^+/Ag = +0.80 \ V, E^o Co^{2+}/Co = -0.28 \ V$

Similar Questions

What is electrode potential in a galvanic cell? Explain in detail.

For the half-cell $Zn^{2+} | Zn$,the standard electrode potential $E^{\circ}$ is $-0.76 \ V$. What is the $e.m.f.$ of the cell $Zn_{(s)} | Zn^{2+}_{(aq)} (1 \ M) || 2H^{+}_{(aq)} (1 \ M) | H_{2(g)} (1 \ atm)$ in $V$?

Given the standard electrode potentials:
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Arrange these metals in their increasing order of reducing power.

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Consider the reaction $M_{(aq)}^{n+} + n e^{-} \to M_{(s)}$. The standard reduction potential values of the elements $M_1$,$M_2$,and $M_3$ are $-0.34 \ V$,$-3.05 \ V$,and $-1.66 \ V$ respectively. The order of their reducing power will be

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Based on the given standard electrode potentials,identify the metal that can be displaced from its salt solution by all other metals listed.$E^o Zn^{2+}/Zn = -0.76 \ V, E^o Cu^{2+}/Cu = +0.34 \ V$$E^o Ag^+/Ag = +0.80 \ V, E^o Co^{2+}/Co = -0.28 \ V$