For which of the following d^n configurations | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In octahedral complexes,the $d$-orbitals split into $t_{2g}$ and $e_g$ sets.For $d^1, d^2, d^3$ configurations,electrons fill the $t_{2g}$ orbital

Vedclass · Accepted Answer

$I$ & $IV$

Vedclass · Answer

(B) In octahedral complexes,the $d$-orbitals split into $t_{2g}$ and $e_g$ sets.For $d^1, d^2, d^3$ configurations,electrons fill the $t_{2g}$ orbitals first,and there is no ambiguity regarding high or low spin.For $d^4, d^5, d^6, d^7$ configurations,electrons can either pair up in $t_{2g}$ (low spin) or occupy $e_g$ (high spin) depending on the field strength of the ligand.For $d^8, d^9, d^{10}$ configurations,the filling pattern is fixed by Hund's rule and the Pauli exclusion principle,resulting in only one possible spin state.Therefore,$d^3$ and $d^8$ configurations do not exhibit high spin and low spin forms.

For which of the following $d^n$ configurations of octahedral complexes,can they $NOT$ exist in both high spin and low spin forms?
$(I)$ $d^3$,$(II)$ $d^5$,$(III)$ $d^6$,$(IV)$ $d^8$

Similar Questions

$A$ coordination compound is made of $Co^{3+}$,$NH_3$,and $Cl^{-}$. $A$ $0.1 \ M$ solution of this complex when treated with excess silver nitrate gave no precipitate. The formula of the complex and secondary valency of metal are respectively.

The geometry,hybridization,and magnetic moment of the ions $[Ni(CN)_4]^{2-}$,$[MnBr_4]^{2-}$,and $[FeF_6]^{4-}$ respectively are:

In the $Cu$-ammonia complex,the state of hybridization of $Cu^{2+}$ is:

The number of unpaired electrons in $Ni(CO)_4$ is

The hybridization of $Ag^+$ in the linear complex $[Ag(NH_3)_2]^+$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

For which of the following $d^n$ configurations of octahedral complexes,can they $NOT$ exist in both high spin and low spin forms?$(I)$ $d^3$,$(II)$ $d^5$,$(III)$ $d^6$,$(IV)$ $d^8$