For the reaction shown,which statement is cor | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The reaction shown is the Hofmann bromamide degradation of $2$-methylbenzamide using $NaOBr$,which yields $2$-methylaniline (o-toluidine) as Produ

Vedclass · Accepted Answer

It has one isomer of $2^\circ$ amine.

Vedclass · Answer

(C) The reaction shown is the Hofmann bromamide degradation of $2$-methylbenzamide using $NaOBr$,which yields $2$-methylaniline (o-toluidine) as Product "$X$".$2$-methylaniline is a primary aromatic amine $(Ar-NH_2)$.$1$. It reacts with Hinsberg's reagent (benzenesulfonyl chloride) to form a sulfonamide,which is soluble in alkali.$2$. It reacts with nitrous acid $(HNO_2)$ at $0-5^{\circ}C$ to form a diazonium salt,which gives a positive Azo dye test with $\beta$-naphthol.$3$. It is a primary amine,and its $2^\circ$ amine isomer is $N$-methylaniline $(C_6H_5NHCH_3)$.$4$. Primary aromatic amines are generally insoluble in aqueous $NaOH$ because they are basic in nature,not acidic.Therefore,the correct statement is that it has one isomer of $2^\circ$ amine,which is $N$-methylaniline.

For the reaction shown,which statement is correct for Product "$X$"?

Similar Questions

The reaction of $N,N'$-diphenylthiourea with concentrated $HCl$ upon heating is given by:
$(C_6H_5NH)_2C=S \xrightarrow{conc. HCl, Heat} A + B$
The unknown compounds $A$ and $B$ in the above reaction are:

Which of the following statements is true for Benzenediazonium fluoroborate?

What is the product formed when ethylamine is oxidized with acidic $KMnO_4$?

The correct order of increasing basic nature for the bases $NH_3$,$CH_3NH_2$ and $(CH_3)_2NH$ is

In the sequence of the following reactions,$X$ and $Y$ are respectively: $CH_3OH$ $\xrightarrow{HI} CH_3I$ $\xrightarrow{KCN} CH_3CN$ $\xrightarrow{\text{reduction}} X$ $\xrightarrow{HNO_2} Y$

Vedclass Test Series

Exam Paper Generator

Online Exam Module