For the reaction $3\,{A_{\,(g)\,}}\,\xrightarrow{K}\,{B_{(g)}}\, + \,\,{C_{(g)\,,}}K$ is ${10^{ - 14}}\,L/mol.\min .$ if $(A) = 0.5\,M$ then the value of $ - \frac{{d(A)}}{{dt}}$ (in $M / sec$ ) is.
$7.5\times 10^{-5}$
$3\times 10^{-4}$
$2.5\times 10^{-5}$
None of these
Reaction : $2Br^{-} + H_2O_2 + 2H^{+} \to Br_2 + 2H_2O$
take place in two steps :
$(a)$ $Br^{-} + H^{+} + H_2O_2 \xrightarrow{{slow}} HOBr + H_2O$
$(b)$ $HOBr + Br^{-} + H^{+} \xrightarrow{{fast}} H_2O + Br_2$
The order of the reaction is
Consider the following gas-phase reaction.
$2HI(g) \longrightarrow H_2(g) + I_2(g)$
and the following experimental data obtained at $555\, K$, What is the order of the reaction with respect to $HI$ $(g)$ ?
$[HI]$, $M$ | rate, $Ms^{-1}$ |
$0.0500$ | $8.80 \times {10^{ - 10}}$ |
$0.1000$ | $3.52 \times {10^{ - 9}}$ |
$0.1500$ | $7.92 \times {10^{ - 9}}$ |
The order of the reaction occurring by following mechanism should be
$(i)$ ${A_2} \to A + A$ (fast)
$(ii)$ $A + {B_2} \to AB + B$ (slow)
$(iii)$ $A + B \to $ (fast)
Which of these does not influence the rate of reaction
The rate law for reaction $A + 2B = C + 2D$ will be