For the following reaction,the yield of the p | vedclass

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(D) The given reaction is an $S_N2$ reaction.$S_N2$ reactions proceed faster in polar aprotic solvents.Polar aprotic solvents like $N,N$-dimethylforma

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$N,N$-dimethylformamide

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(D) The given reaction is an $S_N2$ reaction.$S_N2$ reactions proceed faster in polar aprotic solvents.Polar aprotic solvents like $N,N$-dimethylformamide $(DMF)$ increase the nucleophilicity of the $OH^-$ ion by not solvating it through hydrogen bonding.In contrast,protic solvents like water solvate the nucleophile,reducing its reactivity.Therefore,the yield of the product is highest in $N,N$-dimethylformamide.

For the following reaction,the yield of the product is highest in:
$CH_3-Br + NaOH \to CH_3-OH + NaBr$

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For the following reaction,the yield of the product is highest in:$CH_3-Br + NaOH \to CH_3-OH + NaBr$